Quotient Ring of Cauchy Sequences is Normed Division Ring/Lemma 1
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Theorem
Let $\struct {R, \norm {\, \cdot \,} }$ be a normed division ring.
Let $\CC$ be the ring of Cauchy sequences over $R$
Let $\NN$ be the set of null sequences.
For all $\sequence {x_n} \in \CC$, let $\eqclass {x_n}{}$ denote the left coset $\sequence {x_n} + \NN$
Let $\norm {\, \cdot \,}_1: \CC \, \big / \NN \to \R_{\ge 0}$ be defined by:
- $\ds \forall \eqclass {x_n} {} \in \CC \,\big / \NN: \norm {\eqclass {x_n}{} }_1 = \lim_{n \mathop \to \infty} \norm {x_n}$
Then:
- $\norm {\, \cdot \,}_1$ is well-defined.
That is,
- $(1): \quad \ds \forall \eqclass {x_n}{}: \lim_{n \mathop \to \infty} \norm{x_n}$ exists
- $(2): \quad \ds \forall \eqclass {x_n}{}, \eqclass {y_n}{} \in \CC \,\big / \NN: \eqclass {x_n}{} = \eqclass {y_n}{} \implies \lim_{n \mathop \to \infty} \norm{x_n} = \lim_{n \mathop \to \infty} \norm{y_n}$
Proof
By Norm Sequence of Cauchy Sequence has Limit then:
- for each $\eqclass {x_n}{}$ the $\ds \lim_{n \mathop \to \infty} \norm{x_n}$ exists.
Suppose $\eqclass {x_n}{} = \eqclass {y_n}{}$.
By Left Cosets are Equal iff Difference in Subgroup then:
- $\sequence {x_n} - \sequence {y_n} = \sequence {x_n - y_n} \in \NN$
By Equivalent Cauchy Sequences have Equal Limits of Norm Sequences then:
- $\ds \lim_{n \mathop \to \infty} \norm{x_n} = \lim_{n \mathop \to \infty} \norm{y_n}$
Hence:
- $\ds \norm {\eqclass {x_n}{} }_1 = \lim_{n \mathop \to \infty} \norm{x_n} = \lim_{n \mathop \to \infty} \norm{y_n} = \norm {\eqclass {x_n}{} }_1$
The result follows.
$\blacksquare$
Sources
- 1997: Fernando Q. Gouvea: p-adic Numbers: An Introduction: $\S 3.2$: Completions