Ratio of Lengths of Arms of Pentagram
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Theorem
Consider a pentagram.
Let $AC$ be the length of one of the lines which span the pentagram and define it.
Let $B$ be one of the points where $AC$ intersects one of the other such lines such that $AB > AC$.
Then:
- $\dfrac {AC} {AB} = \phi$
where $\phi$ denotes the golden mean.
Proof
Follows directly from Straight Lines Subtending Two Consecutive Angles in Regular Pentagon cut in Extreme and Mean Ratio.
$\blacksquare$
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Historical Note
The Ratio of Lengths of Arms of Pentagram was known to the Pythagoreans.
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $1 \cdotp 61803 \, 39887 \, 49894 \, 84820 \, 45868 \, 34365 \, 63811 \, 77203 \, 09179 \, 80576 \ldots$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $1 \cdotp 61803 \, 39887 \, 49894 \, 84820 \, 45868 \, 34365 \, 63811 \, 77203 \, 09179 \, 80576 \ldots$
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): golden section