Restricted P-adic Valuation is Valuation
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Theorem
Let $\nu_p^\Z: \Z \to \Z \cup \set {+\infty}$ be the $p$-adic valuation restricted to the integers.
Then $\nu_p^\Z$ is a valuation.
Proof
To prove that $\nu_p^\Z$ is a valuation it is necessary to demonstrate:
\((\text V 1)\) | $:$ | \(\ds \forall m, n \in \Z:\) | \(\ds \map {\nu_p^\Z} {m n} \) | \(\ds = \) | \(\ds \map {\nu_p^\Z} m + \map {\nu_p^\Z} n \) | ||||
\((\text V 2)\) | $:$ | \(\ds \forall n \in \Z:\) | \(\ds \map {\nu_p^\Z} n = +\infty \) | \(\ds \iff \) | \(\ds n = 0 \) | ||||
\((\text V 3)\) | $:$ | \(\ds \forall m, n \in \Z:\) | \(\ds \map {\nu_p^\Z} {m + n} \) | \(\ds \ge \) | \(\ds \min \set {\map {\nu_p^\Z} m, \map {\nu_p^\Z} n} \) |
Axiom $(\text V 1)$
Let $m, n \in \Z$.
Let $m = 0$ or $n = 0$.
Then:
- $\map {\nu_p^\Z} m = +\infty$
or:
- $\map {\nu_p^\Z} n = +\infty$
Also:
- $n m = 0$
and hence:
\(\ds \map {\nu_p^\Z} {n m}\) | \(=\) | \(\ds +\infty\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map {\nu_p^\Z} n + \map {\nu_p^\Z} m\) |
Let $n m \ne 0$.
Then by definition of the restricted $p$-adic valuation:
- $p^{\map {\nu_p^\Z} n} \divides n$
- $p^{\map {\nu_p^\Z} n + 1} \nmid n$
Also:
- $p^{\map {\nu_p^\Z} m} \divides m$
- $p^{\map {\nu_p^\Z} m + 1} \nmid m$
Hence:
- $p^{\map {\nu_p^\Z} n + \map {\nu_p^\Z} m} \divides n m$
- $p^{\map {\nu_p^\Z} n + \map {\nu_p^\Z} m + 1} \nmid n m$
So:
- $\map {\nu_p^\Z} {n m} = \map {\nu_p^\Z} n + \map {\nu_p^\Z} m$
$\Box$
Axiom $(\text V 2)$
By definition of the restricted $p$-adic valuation:
- $\forall n \in \Z: \map {\nu_p^\Z} n = +\infty \iff n = 0$
$\Box$
Axiom $(\text V 3)$
Let $m, n \in \Z$.
Without loss of generality let:
- $p^\alpha \divides n$
- $p^\beta \divides m$
where $\alpha \ge \beta$.
Then $\exists t \in \Z, k \in \Z$ such that:
\(\ds n + m\) | \(=\) | \(\ds p^\alpha k + p^\beta t\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds p^\beta \paren {p^{\alpha - \beta} k + t}\) |
Thus:
- $p^\beta \divides \paren {m + n}$
$\Box$
Hence by the definition of $\nu_p^\Z$:
- $\map {\nu_p^\Z} {m + n} \ge \min \set {\map {\nu_p^\Z} m, \map {\nu_p^\Z} n}$
$\blacksquare$