Riemann Zeta Function at Even Integers/Corollary

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Corollary to Riemann Zeta Function at Even Integers

\(\ds B_{2 n}\) \(=\) \(\ds \paren {-1}^{n + 1} \dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} } \sum_{k \mathop = 1}^\infty \frac 1 {k^{2 n} }\)
\(\ds \) \(=\) \(\ds \paren {-1}^{n + 1} \dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} } \paren {1 + \frac 1 {2^{2 n} } + \frac 1 {3^{2 n} } + \cdots}\)

where:

$B_n$ are the Bernoulli numbers
$n$ is a positive integer.


Proof

\(\ds \paren {-1}^{n + 1} \dfrac {B_{2 n} 2^{2 n - 1} \pi^{2 n} } {\paren {2 n}!}\) \(=\) \(\ds \map \zeta {2 n}\) Riemann Zeta Function at Even Integers
\(\ds \) \(=\) \(\ds \sum_{k \mathop = 1}^\infty \frac 1 {k^{2 n} }\) Definition of Riemann Zeta Function
\(\ds \leadsto \ \ \) \(\ds \paren {-1}^{n + 1} B_{2 n}\) \(=\) \(\ds \dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} } \sum_{k \mathop = 1}^\infty \frac 1 {k^{2 n} }\) multiplying both sides by $\dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} }$
\(\ds \leadsto \ \ \) \(\ds \paren {-1}^{2 n + 2} B_{2 n}\) \(=\) \(\ds \paren {-1}^{n + 1} \dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} } \sum_{k \mathop = 1}^\infty \frac 1 {k^{2 n} }\) multiplying both sides by $\paren {-1}^{n + 1}$
\(\ds \leadsto \ \ \) \(\ds B_{2 n}\) \(=\) \(\ds \paren {-1}^{n + 1} \dfrac {\paren {2 n}!} {2^{2 n - 1} \pi^{2 n} } \sum_{k \mathop = 1}^\infty \frac 1 {k^{2 n} }\) $\paren {-1}^{2 n + 2} = 1$ as $2 n + 2$ is even

$\blacksquare$


Sources

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