Ring of Polynomials over Reals is not Field
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Theorem
Let $\R \sqbrk X$ be the ring of polynomials in an indeterminate $X$ over $\R$.
Then $\R \sqbrk X$ is not a field.
Proof
Consider the polynomial $x + 1$ in $\R \sqbrk X$.
There exists no polynomial $\map f x$ such that:
- $\paren {x + 1} \map f x = 1$
This is because the left hand side has degree $1$, and the right hand side has degree $0$.
$\blacksquare$
Sources
- 1969: C.R.J. Clapham: Introduction to Abstract Algebra ... (previous) ... (next): Chapter $4$: Fields: $\S 15$. Examples of Fields: Example $19$