Rule of Idempotence/Disjunction/Formulation 2
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Theorem
The disjunction operation is idempotent:
- $\vdash p \iff \paren {p \lor p}$
This can be expressed as two separate theorems:
Forward Implication
- $\vdash p \implies \left({p \lor p}\right)$
Reverse Implication
- $\vdash \left({p \lor p}\right) \implies p$
Proof
By the tableau method of natural deduction:
Line | Pool | Formula | Rule | Depends upon | Notes | |
---|---|---|---|---|---|---|
1 | 1 | $p$ | Assumption | (None) | ||
2 | 1 | $p \lor p$ | Rule of Addition: $\lor \II_1$ | 1 | ||
3 | $p \implies \paren {p \lor p}$ | Rule of Implication: $\implies \II$ | 1 – 2 | Assumption 1 has been discharged | ||
4 | 4 | $p \lor p$ | Assumption | (None) | ||
5 | 5 | $\neg p$ | Assumption | (None) | ||
6 | 4, 5 | $p$ | Modus Tollendo Ponens $\mathrm {MTP}_1$ | 4, 5 | ||
7 | 4, 5 | $\bot$ | Principle of Non-Contradiction: $\neg \EE$ | 6, 5 | ||
8 | 5 | $p$ | Proof by Contradiction: $\neg \II$ | 5 – 7 | Assumption 5 has been discharged | |
9 | $\paren {p \lor p} \implies p$ | Rule of Implication: $\implies \II$ | 4 – 8 | Assumption 4 has been discharged | ||
10 | $p \iff \paren {p \lor p}$ | Biconditional Introduction: $\iff \II$ | 3, 9 |
$\blacksquare$
Sources
- 1946: Alfred Tarski: Introduction to Logic and to the Methodology of Deductive Sciences (2nd ed.) ... (previous) ... (next): $\S \text{II}.13$: Symbolism of sentential calculus
- 1964: Donald Kalish and Richard Montague: Logic: Techniques of Formal Reasoning ... (previous) ... (next): $\text{II}$: 'AND', 'OR', 'IF AND ONLY IF': $\S 5$: Theorem $\text{T47}$
- 1973: Irving M. Copi: Symbolic Logic (4th ed.) ... (previous) ... (next): $3$: The Method of Deduction: $3.2$: The Rule of Replacement: $19.$
- 1980: D.J. O'Connor and Betty Powell: Elementary Logic ... (previous) ... (next): $\S \text{II}$: The Logic of Statements $(2)$: The remaining rules of inference: $18$
- 1982: P.M. Cohn: Algebra Volume 1 (2nd ed.) ... (previous) ... (next): Chapter $1$: Sets and mappings: $\S 1.1$: The need for logic: Exercise $(1) \ \text{(ii)}$