Rule of Simplification/Sequent Form/Formulation 2
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Theorem
The Rule of Simplification can be symbolised by the sequents:
- $(1): \quad \vdash p \land q \implies p$
- $(2): \quad \vdash p \land q \implies q$
Form 1
- $\vdash p \land q \implies p$
Form 2
- $\vdash p \land q \implies q$
Proof 1
Form 1
By the tableau method of natural deduction:
Line | Pool | Formula | Rule | Depends upon | Notes | |
---|---|---|---|---|---|---|
1 | 1 | $p \land q$ | Assumption | (None) | ||
2 | 1 | $p$ | Rule of Simplification: $\land \EE_1$ | 1 | ||
3 | $p \land q \implies p$ | Rule of Implication: $\implies \II$ | 1 – 2 | Assumption 1 has been discharged |
$\blacksquare$
Form 2
By the tableau method of natural deduction:
Line | Pool | Formula | Rule | Depends upon | Notes | |
---|---|---|---|---|---|---|
1 | 1 | $p \land q$ | Assumption | (None) | ||
2 | 1 | $q$ | Rule of Simplification: $\land \EE_2$ | 1 | ||
3 | $p \land q \implies q$ | Rule of Implication: $\implies \II$ | 1 – 2 | Assumption 1 has been discharged |
$\blacksquare$
Proof 2
We apply the Method of Truth Tables.
As can be seen by inspection, the truth values under the main connective are $T$ for all boolean interpretations.
$\begin{array}{|ccc|c|c||c|c|} \hline p & \land & q & p & q & p \land q \implies p & p \land q \implies q \\ \hline F & F & F & F & F & T & T \\ F & F & T & F & T & T & T \\ T & F & F & T & F & T & T \\ T & T & T & T & T & T & T \\ \hline \end{array}$
$\blacksquare$