Secant of Zero
(Redirected from Secant of 0 Degrees)
Jump to navigation
Jump to search
Theorem
- $\sec 0 = 0$
where $\sec$ denotes secant.
Proof
\(\ds \sec 0 \degrees\) | \(=\) | \(\ds \frac 1 {\cos 0 \degrees}\) | Secant is Reciprocal of Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 1\) | Cosine of Zero is One | |||||||||||
\(\ds \) | \(=\) | \(\ds 1\) |
$\blacksquare$
Also see
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 5$: Trigonometric Functions: Exact Values for Trigonometric Functions of Various Angles