Sequence of Numbers Divisible by Sequence of Primes

Theorem

The integers in this sequence:

$788, 789, 790, 791, 792, 793$

are divisible by:

$2, 3, 5, 7, 11, 13$

respectively.

Proof

\(\ds 788\)

\(=\)

\(\ds 2 \times 394\)

\(\ds 789\)

\(=\)

\(\ds 3 \times 263\)

\(\ds 790\)

\(=\)

\(\ds 5 \times 158\)

\(\ds 791\)

\(=\)

\(\ds 7 \times 113\)

\(\ds 792\)

\(=\)

\(\ds 11 \times 72\)

\(\ds 793\)

\(=\)

\(\ds 13 \times 61\)

$\blacksquare$

Sources

• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $788$