Set Union is Self-Distributive/Families of Sets
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Theorem
Let $I$ be an indexing set.
Let $\family {A_\alpha}_{\alpha \mathop \in I}$ and $\family {B_\alpha}_{\alpha \mathop \in I}$ be indexed families of subsets of a set $S$.
Then:
- $\ds \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha} = \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha}$
where $\ds \bigcup_{\alpha \mathop \in I} A_\alpha$ denotes the union of $\family {A_\alpha}_{\alpha \mathop \in I}$.
Proof
\(\ds x\) | \(\in\) | \(\ds \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \exists \beta \in I: \, \) | \(\ds x\) | \(\in\) | \(\ds A_\beta \cup B_\beta\) | Definition of Union of Family | |||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(\in\) | \(\ds A_\beta\) | Definition of Set Union | ||||||||||
\(\, \ds \lor \, \) | \(\ds x\) | \(\in\) | \(\ds B_\beta\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(\in\) | \(\ds \bigcup_{\alpha \mathop \in I} A_\alpha\) | Set is Subset of Union of Family | ||||||||||
\(\, \ds \lor \, \) | \(\ds x\) | \(\in\) | \(\ds \bigcup_{\alpha \mathop \in I} B_\alpha\) | Set is Subset of Union of Family | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(\in\) | \(\ds \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha}\) | Definition of Set Union |
Thus by definition of subset:
- $\ds \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha} \subseteq \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha}$
$\Box$
\(\ds x\) | \(\in\) | \(\ds \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(\in\) | \(\ds \bigcup_{\alpha \mathop \in I} A_\alpha\) | Definition of Set Union | ||||||||||
\(\, \ds \lor \, \) | \(\ds x\) | \(\in\) | \(\ds \bigcup_{\alpha \mathop \in I} B_\alpha\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \exists \beta \in I: \, \) | \(\ds x\) | \(\in\) | \(\ds A_\beta\) | Definition of Union of Family | |||||||||
\(\ds \exists \beta \in I: \, \) | \(\, \ds \lor \, \) | \(\ds x\) | \(\in\) | \(\ds B_\beta\) | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \exists \beta \in I: \, \) | \(\ds x\) | \(\in\) | \(\ds A_\beta \cup B_\beta\) | Definition of Union of Family | |||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(\in\) | \(\ds \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha}\) |
Thus by definition of subset:
- $\ds \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha} \subseteq \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha}$
$\Box$
By definition of set equality:
- $\ds \map {\bigcup_{\alpha \mathop \in I} } {A_\alpha \cup B_\alpha} = \paren {\bigcup_{\alpha \mathop \in I} A_\alpha} \cup \paren {\bigcup_{\alpha \mathop \in I} B_\alpha}$
$\blacksquare$
Sources
- 1975: Bert Mendelson: Introduction to Topology (3rd ed.) ... (previous) ... (next): Chapter $1$: Theory of Sets: $\S 4$: Indexed Families of Sets: Exercise $1 \ \text{(c)}$
- 1993: Keith Devlin: The Joy of Sets: Fundamentals of Contemporary Set Theory (2nd ed.) ... (previous) ... (next): $\S 1$: Naive Set Theory: $\S 1.4$: Sets of Sets: Exercise $1.4.4 \ \text{(iii)}$