Stabilizer of Cartesian Product of Group Actions
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Theorem
Let $\struct {G, \circ}$ be a group.
Let $S$ and $T$ be sets.
Let $*_S: G \times S \to S$ and $*_T: G \times T \to T$ be group actions.
Let the group action $*: G \times \paren {S \times T} \to S \times T$ be defined as:
- $\forall \tuple {g, \tuple {s, t} } \in G \times \paren {S \times T}: g * \tuple {s, t} = \tuple {g *_S s, g *_T t}$
Then the stabilizer of $\tuple {s, t} \in S \times T$ is given by:
- $\Stab {s, t} = \Stab s \cap \Stab t$
where $\Stab s$ and $\Stab t$ are the stabilizers of $s$ and $t$ under $*_S$ and $*_T$ respectively.
Proof
By definition, the stabilizer of an element $x$ of $S$ is defined as:
- $\Stab x := \set {g \in G: g * x = x}$
where $*$ denotes the group action.
So:
\(\ds \Stab {s, t}\) | \(=\) | \(\ds \set {g \in G: g * \tuple {s, t} = \tuple {s, t} }\) | Definition of Stabilizer | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {g \in G: \tuple {g *_S s, g *_T t} = \tuple {s, t} }\) | Definition of $*$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {g \in G: g *_S s = s \land g *_T t = t}\) | Definition of Cartesian Product | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {g \in G: g \in \Stab s \land g \in \Stab t}\) | Definition of Stabilizer | |||||||||||
\(\ds \) | \(=\) | \(\ds \Stab s \cap \Stab t\) | Definition of Set Intersection |
$\blacksquare$
Sources
- 1982: P.M. Cohn: Algebra Volume 1 (2nd ed.) ... (previous) ... (next): $\S 3.3$: Group actions and coset decompositions: Exercise $3$