Strongly Locally Compact Space is Weakly Locally Compact
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Theorem
Let $T = \struct {S, \tau}$ be a strongly locally compact space.
Then $T$ is weakly locally compact.
Proof
Let $T = \struct {S, \tau}$ be strongly locally compact.
Let $x \in S$.
By definition, there exists an open set $U_x$ of $T$ such that:
From Set is Subset of its Topological Closure, $U_x \subseteq {U_x}^-$ and so $x \in {U_x}^-$.
Thus $x$ is contained in a compact neighborhood.
As this holds for all $x$, $T$ is a weakly locally compact.
$\blacksquare$
Also see
- Locally Compact Space is Weakly Locally Compact
- Sequence of Implications of Local Compactness Properties
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text I$: Basic Definitions: Section $3$: Compactness: Localized Compactness Properties