Subset of Set with Propositional Function

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $S$ be a set.

Let $P: S \to \set {\T, \F}$ be a propositional function on $S$.


Then:

$\set {x \in S: \map P x} \subseteq S$


Proof

\(\ds s\) \(\in\) \(\ds \set {x \in S: \map P x}\)
\(\ds \leadsto \ \ \) \(\ds s\) \(\in\) \(\ds \set {x \in S \land \map P x}\)
\(\ds \leadsto \ \ \) \(\ds s\) \(\in\) \(\ds \set {x \in S} \land \map P s\) Definition of Set Definition by Predicate
\(\ds \leadsto \ \ \) \(\ds s\) \(\in\) \(\ds \set {x \in S}\) Rule of Simplification
\(\ds \leadsto \ \ \) \(\ds s\) \(\in\) \(\ds S\) Definition of Element
\(\ds \leadsto \ \ \) \(\ds \set {x \in S: \map P x}\) \(\subseteq\) \(\ds S\) Definition of Subset

$\blacksquare$


Sources