Subspace of Product Space is Homeomorphic to Factor Space/Proof 2/Open Mapping
Theorem
Let $\family {\struct {X_i, \tau_i} }_{i \mathop \in I}$ be a family of topological spaces where $I$ is an arbitrary index set.
Let $\ds \struct {X, \tau} = \prod_{i \mathop \in I} \struct {X_i, \tau_i}$ be the product space of $\family {\struct {X_i, \tau_i} }_{i \mathop \in I}$.
Let $z \in X$.
Let $i \in I$.
Let $Y_i = \set {x \in X: \forall j \in I \setminus \set i: x_j = z_j}$.
Let $\upsilon_i$ be the subspace topology of $Y_i$ relative to $\tau$.
Let $p_i = \pr_i {\restriction_{Y_i} }$, where $\pr_i$ is the projection from $X$ to $X_i$.
Then:
- $p_i$ is an open mapping.
Proof
Let $U \in \upsilon_i$.
Let $x \in \map {p_i^\to} U$.
Then by definition of the direct image mapping:
- $\exists y \in U : x = \map {p_i} y$
By the definition of the subspace topology:
- $\exists U' \in \tau: U = U' \cap Y_i$
For all $k \in I$ let $\pr_k$ denote the projection from $X$ to $X_k$.
By definition of the natural basis of the product topology $\tau$:
and:
- for each $k \in J$, there exists a $V_k \in \tau_k$
such that:
- $\ds y \in \bigcap_{k \mathop \in J} \map {\pr_k^\gets} {V_k} \subseteq U'$
Then:
- $\ds y \in \paren {\bigcap_{k \mathop \in J} \map{\pr_k^\gets} {V_k} } \cap Y_i \subseteq U' \cap Y_i = U$
By definition of direct image mapping:
- $\ds x = \map {p_i} y \in \map {p_i^\to} {\paren {\bigcap_{k \mathop \in J} \map {\pr_k^\gets} {V_k} } \cap Y_i} \subseteq \map {p_i^\to} U$
Recall that $p_i$ is an injection.
Then:
\(\ds \map {p_i^\to} {\paren {\bigcap_{k \mathop \in J} \map {\pr_k^\gets} {V_k} } \cap Y_i}\) | \(=\) | \(\ds \map {p_i^\to} {\bigcap_{k \mathop \in J} \paren {\map {\pr_k^\gets} {V_k} \cap Y_i} }\) | Set Intersection is Self-Distributive | |||||||||||
\(\ds \) | \(=\) | \(\ds \bigcap_{k \mathop \in J} \map {p_i^\to} {\map {\pr_k^\gets } {V_k} \cap Y_i}\) | Image of Intersection under Injection |
Let $k \in J$.
Lemma
- $\map {p_i^\to} {\map {\pr_k^\gets} {V_k} \cap Y_i}$ is open in $\struct{X_i, \tau_i}$
$\Box$
By Open Set Axiom $\paren {\text O 1 }$: Union of Open Sets:
- $\ds \bigcap_{k \mathop \in J} \map {p_i^\to} {\map{\pr_k^\gets} {V_k} \cap Y_i}$ is open in $\struct {X_i, \tau_i}$
Since $x \in \map {p_i^\to} U$ was arbitrary then it has been shown that:
- $\forall x \in \map {p_i^\to} U : \exists V \in \tau_i : x \in V \subseteq \map {p_i^\to} U$
Then by definition: $\forall x \in \map {p_i^\to} U: \map {p_i^\to} U$ is a neighborhood of $x$.
From Set is Open iff Neighborhood of all its Points:
- $\map {p_i^\to} U$ is open in $\tau_i$.
Since $U \in \upsilon_i$ was arbitrary, $p_i$ is an open mapping.
$\blacksquare$