Successor Mapping on Natural Numbers is Progressing/Proof 1
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Theorem
Let $\omega$ denote the set of natural numbers as defined by the von Neumann construction.
Let $s: \omega \to \omega$ denote the successor mapping on $\omega$.
Then $s$ is a progressing mapping.
Proof
By definition of the von Neumann construction:
- $n^+ = n \cup \set n$
from which it follows that:
- $n \subseteq n^+$
Hence the result by definition of progressing mapping.
$\blacksquare$