Supremum of Lower Sums Never Greater than Upper Sum
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Theorem
Let $\closedint a b$ be a closed real interval .
Let $f$ be a bounded real function defined on $\closedint a b$.
Let $S$ be a finite subdivision of $\closedint a b$.
Let $\map U S$ be the upper Darboux sum of $f$ on $\closedint a b$ with respect to $S$.
Let $\map L P$ be the lower Darboux sum of $f$ on $\closedint a b$ with respect to a finite subdivision $P$.
Then:
- $\sup_P \map L P \le \map U S$
Proof
From Upper Sum Never Smaller than Lower Sum for any Pair of Subdivisions, $\map U S$ is an upper bound for the real set:
- $T = \leftset {\map L P: P}$ is a finite subdivision of $\rightset {\closedint a b}$
Since $\sup_P \map L P$ is the supremum of $T$:
- $\sup_P \map L P \le \map U S$
Hence the result.
$\blacksquare$