Topologies on Set with 3 Elements

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Theorem

Let $S = \set {a, b, c}$ be a set with $3$ elements.

Then there exist $29$ possible different topologies on $S$:

\(\ds \tau_1\) \(=\) \(\ds \set {\O, \set {a, b, c} }\) Indiscrete Topology
\(\ds \tau_2\) \(=\) \(\ds \set {\O, \set a, \set b, \set c, \set {a, b}, \set {a, c}, \set {b, c}, \set {a, b, c} }\) Discrete Topology
\(\ds \tau_3\) \(=\) \(\ds \set {\O, \set {a, b}, S}\) Included Set Topology, where the included set is $\set {a, b}$
\(\ds \tau_4\) \(=\) \(\ds \set {\O, \set {a, c}, S}\) Included Set Topology, where the included set is $\set {a, c}$
\(\ds \tau_5\) \(=\) \(\ds \set {\O, \set {b, c}, S}\) Included Set Topology, where the included set is $\set {b, c}$
\(\ds \tau_6\) \(=\) \(\ds \set {\O, \set a, S}\) Excluded Set Topology, where the excluded set is $\set {b, c}$
\(\ds \tau_7\) \(=\) \(\ds \set {\O, \set b, S}\) Excluded Set Topology, where the excluded set is $\set {a, c}$
\(\ds \tau_8\) \(=\) \(\ds \set {\O, \set c, S}\) Excluded Set Topology, where the excluded set is $\set {a, b}$
\(\ds \tau_9\) \(=\) \(\ds \set {\O, \set a, \set {b, c}, S}\) Partition Topology, where the partition is $\set {a \mid b, c}$
\(\ds \tau_{10}\) \(=\) \(\ds \set {\O, \set b, \set {a, c}, S}\) Partition Topology, where the partition is $\set {b \mid a, c}$
\(\ds \tau_{11}\) \(=\) \(\ds \set {\O, \set c, \set {a, b}, S}\) Partition Topology, where the partition is $\set {c \mid a, b}$
\(\ds \tau_{12}\) \(=\) \(\ds \set {\O, \set a, \set {a, b}, S}\) Order Topology, where the total ordering is $a \preccurlyeq b \preccurlyeq c$
\(\ds \tau_{13}\) \(=\) \(\ds \set {\O, \set b, \set {a, b}, S}\) Order Topology, where the total ordering is $b \preccurlyeq a \preccurlyeq c$
\(\ds \tau_{14}\) \(=\) \(\ds \set {\O, \set a, \set {a, c}, S}\) Order Topology, where the total ordering is $a \preccurlyeq c \preccurlyeq b$
\(\ds \tau_{15}\) \(=\) \(\ds \set {\O, \set c, \set {a, c}, S}\) Order Topology, where the total ordering is $c \preccurlyeq a \preccurlyeq b$
\(\ds \tau_{16}\) \(=\) \(\ds \set {\O, \set b, \set {b, c}, S}\) Order Topology, where the total ordering is $b \preccurlyeq c \preccurlyeq a$
\(\ds \tau_{17}\) \(=\) \(\ds \set {\O, \set c, \set {b, c}, S}\) Order Topology, where the total ordering is $c \preccurlyeq b \preccurlyeq a$
\(\ds \tau_{18}\) \(=\) \(\ds \set {\O, \set a, \set {a, b}, \set {a, c}, S}\) Particular Point Topology, where the particular point is $a$
\(\ds \tau_{19}\) \(=\) \(\ds \set {\O, \set b, \set {a, b}, \set {b, c}, S}\) Particular Point Topology, where the particular point is $b$
\(\ds \tau_{20}\) \(=\) \(\ds \set {\O, \set c, \set {a, c}, \set {b, c}, S}\) Particular Point Topology, where the particular point is $c$
\(\ds \tau_{21}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, S}\) Excluded Point Topology, where the excluded point is $c$
\(\ds \tau_{22}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, c}, S}\) Excluded Point Topology, where the excluded point is $b$
\(\ds \tau_{23}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {b, c}, S}\) Excluded Point Topology, where the excluded point is $a$
\(\ds \tau_{24}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, \set {a, c}, S}\)
\(\ds \tau_{25}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{26}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, b}, \set {a, c}, S}\)
\(\ds \tau_{27}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{28}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{29}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {a, c}, \set {b, c}, S}\)

The numbering is arbitrary.


Proof

The power set of $S$ is the set:

$\powerset S = \set {\O, \set a, \set b, \set c, \set {a, b}, \set {a, c}, \set {b, c}, \set {a, b, c} }$

A topology on $S$ is a subset of $\powerset S$.

Thus the set of all topologies on $S$ is a subset of the power set of $\powerset S$.

From Cardinality of Power Set of Finite Set:

$\card {\powerset {\powerset S} } = 256$

Half of the subsets of $\powerset {\powerset S}$ do not contain $\O$ and so are not topologies on $S$.

Half of the remaining subsets of $\powerset {\powerset S}$ do not contain $S$ itself, and so are also not topologies on $S$.

We are left with $64$ subsets of $\powerset {\powerset S}$ to investigate.

In the following, they will be numbered arbitrarily.


First we have the discrete topology and indiscrete topology on $S$:

\(\ds \tau_1\) \(=\) \(\ds \set {\O, S}\)
\(\ds \tau_2\) \(=\) \(\ds \set {\O, \set a, \set b, \set c, \set {a, b}, \set {a, c}, \set {b, c}, S}\)

$\Box$


From here, we investigate topologies according to the number of its singletons.


Before doing that, note that a topology on $S$ with either $3$ singletons or $3$ doubletons is the discrete topology.

Hence in the below we need only investigate topologies with $0$, $1$ and $2$ singletons and doubletons.


Topologies with no Singletons

Let $\TT_0$ be a topology on $S$ which does not contain a singleton.

Unless $\TT_0$ is the indiscrete topology, $\TT_0$ must therefore contain at least one doubleton.

Aiming for a contradiction, suppose there exist $2$ distinct doubletons $S_1$ and $S_2$ of $\powerset S$ such that $S_1, S_2 \in \TT_0$.

Their intersection $S_1 \cap S_2$ cannot be $\O$ as then there would be at least $4$ distinct elements in $S$.

On the other hand, $S_1 \cap S_2$ cannot have $2$ distinct elements otherwise $S_1 = S_2$.

So $S_1 \cap S_2$ is a singleton.

But because $\TT_0$ be a topology, $S_1 \cap S_2 \in \TT_0$.

But this contradicts our assertion that $\TT_0$ does not contain a singleton.

So for $\TT_0$ to be a topology, $\TT_0$ must contain exactly $1$ doubleton.

Hence we have the included set topologies on $S$:

\(\ds \tau_3\) \(=\) \(\ds \set {\O, \set {a, b}, S}\) where the included set is $\set {a, b}$
\(\ds \tau_4\) \(=\) \(\ds \set {\O, \set {a, c}, S}\) where the included set is $\set {a, c}$
\(\ds \tau_5\) \(=\) \(\ds \set {\O, \set {b, c}, S}\) where the included set is $\set {b, c}$

$\Box$


Topologies with $1$ Singleton

Let $\TT_1$ be a topology on $S$ which contains exactly $1$ singleton $U$.

First we note that by adding just $1$ singleton to the indiscrete topology on $S$ yields the excluded set topologies on $S$:

\(\ds \tau_6\) \(=\) \(\ds \set {\O, \set a, S}\) where the excluded set is $\set {b, c}$
\(\ds \tau_7\) \(=\) \(\ds \set {\O, \set b, S}\) where the excluded set is $\set {a, c}$
\(\ds \tau_8\) \(=\) \(\ds \set {\O, \set c, S}\) where the excluded set is $\set {a, b}$


Now consider topologies $\TT_1$ on $S$ which contain exactly one doubleton.

Let us add one doubleton $D$ to each of these topologies which contains one singleton $U$.

First suppose that $D \cap U = \O$.

Thus we have the partition topologies on $S$:

\(\ds \tau_9\) \(=\) \(\ds \set {\O, \set a, \set {b, c}, S}\) where the partition is $\set {a \mid b, c}$
\(\ds \tau_{10}\) \(=\) \(\ds \set {\O, \set b, \set {a, c}, S}\) where the partition is $\set {b \mid a, c}$
\(\ds \tau_{11}\) \(=\) \(\ds \set {\O, \set c, \set {a, b}, S}\) where the partition is $\set {c \mid a, b}$


Now suppose that $D \cap U \ne \O$.

Thus we find we have the order topologies on $S$:

\(\ds \tau_{12}\) \(=\) \(\ds \set {\O, \set a, \set {a, b}, S}\) where the total ordering is $a \preccurlyeq b \preccurlyeq c$
\(\ds \tau_{13}\) \(=\) \(\ds \set {\O, \set b, \set {a, b}, S}\) where the total ordering is $b \preccurlyeq a \preccurlyeq c$
\(\ds \tau_{14}\) \(=\) \(\ds \set {\O, \set a, \set {a, c}, S}\) where the total ordering is $a \preccurlyeq c \preccurlyeq b$
\(\ds \tau_{15}\) \(=\) \(\ds \set {\O, \set c, \set {a, c}, S}\) where the total ordering is $c \preccurlyeq a \preccurlyeq b$
\(\ds \tau_{16}\) \(=\) \(\ds \set {\O, \set b, \set {b, c}, S}\) where the total ordering is $b \preccurlyeq c \preccurlyeq a$
\(\ds \tau_{17}\) \(=\) \(\ds \set {\O, \set c, \set {b, c}, S}\) where the total ordering is $c \preccurlyeq b \preccurlyeq a$


Now consider topologies $\TT_1$ on $S$ which contain exactly $2$ doubletons $D_1$ and $D_2$ in addition to its one singleton $U$.

First consider the situation where $D_1 \cap D_2 = U$.

Thus we have the particular point topologies on $S$:

\(\ds \tau_{18}\) \(=\) \(\ds \set {\O, \set a, \set {a, b}, \set {a, c}, S}\) where the particular point is $a$
\(\ds \tau_{19}\) \(=\) \(\ds \set {\O, \set b, \set {a, b}, \set {b, c}, S}\) where the particular point is $b$
\(\ds \tau_{20}\) \(=\) \(\ds \set {\O, \set c, \set {a, c}, \set {b, c}, S}\) where the particular point is $c$


Now consider the situation where $D_1 \cap D_2 \ne U$.

Then $D_1 \cap D_2 \in \TT_1$ by definition of topology.

This would mean that $\TT_1$ contains $2$ singletons.

Hence it is not possible for a topology on $S$ with exactly one singleton $U$ to have $2$ doubletons $D_1$ and $D_2$ such that $D_1 \cap D_2 \ne U$.


Thus we have exhausted our list of topologies on $S$ with one singleton.

$\Box$


Topologies with $2$ Singletons

Let $\TT_2$ be a topology on $S$ which contains exactly $2$ singletons: $U_1$ and $U_2$.

We note that $U_1 \cup U_2$ is also in $\TT_2$.

Thus $\TT_2$ contains at least one doubleton.

This fact yields us the excluded point topologies on $S$:

\(\ds \tau_{21}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, S}\) where the excluded point is $c$
\(\ds \tau_{22}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, c}, S}\) where the excluded point is $b$
\(\ds \tau_{23}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {b, c}, S}\) where the excluded point is $a$


Now consider topologies $\TT_2$ on $S$ which contain exactly $2$ doubletons $D_1$ and $D_2$ in addition to its $2$ singletons $U_1$ and $U_2$.

Suppose $D_1 \cap D_2 \notin \set {U_1, U_2}$.

Then $\TT_2$ would contain $3$ singletons.

So we note that $D_1 \cap D_2 = U_1$ or $D_1 \cap D_2 = U_2$.

This yields the following topologies, which do not appear to be instances of a topology of a particular variety:

\(\ds \tau_{24}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, \set {a, c}, S}\)
\(\ds \tau_{25}\) \(=\) \(\ds \set {\O, \set a, \set b, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{26}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, b}, \set {a, c}, S}\)
\(\ds \tau_{27}\) \(=\) \(\ds \set {\O, \set a, \set c, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{28}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {a, b}, \set {b, c}, S}\)
\(\ds \tau_{29}\) \(=\) \(\ds \set {\O, \set b, \set c, \set {a, c}, \set {b, c}, S}\)


That exhausts our possible topologies $\TT_2$ on $S$ which contain exactly $2$ singletons.

$\Box$


Thus we have enumerated all the different topologies on $S$, and the total comes to $29$.

$\blacksquare$


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