Translation of Union of Subsets of Vector Space
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Theorem
Let $K$ be a field.
Let $X$ be a vector space over $K$.
Let $\family {E_\alpha}_{\alpha \mathop \in I}$ be an indexed family of subsets of $X$.
Let $x \in X$.
Then:
- $\ds \paren {\bigcup_{\alpha \mathop \in I} E_\alpha} + x = \bigcup_{\alpha \mathop \in I} \paren {E_\alpha + x}$
where $E_\alpha + x$ denotes the translation of $E_\alpha$ by $x$.
Proof
We have:
- $\ds v \in \paren {\bigcup_{\alpha \mathop \in I} E_\alpha} + x$
- $v = u + x$ for some $\ds u \in \bigcup_{\alpha \mathop \in I} E_\alpha$.
This is equivalent to:
- there exists $\alpha \in I$ and $u \in E_\alpha$ such that $v = u + x$.
That is:
- there exists $\alpha \in I$ such that $v \in E_\alpha + x$.
So by the definition of set equality, we have:
- $\ds \paren {\bigcup_{\alpha \mathop \in I} E_\alpha} + x = \bigcup_{\alpha \mathop \in I} \paren {E_\alpha + x}$
$\blacksquare$