Trivial Relation is Universally Congruent
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Theorem
The trivial relation $\RR = S \times S$ on a set $S$ is universally congruent on $S$.
Proof
Let $\struct {S, \circ}$ be any algebraic structure which is closed for $\circ$.
By definition of trivial relation:
- $x \in S \land y \in S \implies x \mathrel \RR y$
So:
\(\ds x_1, x_2, y_1, y_2\) | \(\in\) | \(\ds S\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds x_1 \circ y_1, x_2 \circ y_2\) | \(\in\) | \(\ds S\) | Definition of Closed Algebraic Structure | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \paren {x_1 \circ y_1}\) | \(\RR\) | \(\ds \paren {x_2 \circ y_2}\) | Definition of Trivial Relation |
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {II}$: New Structures from Old: $\S 11$: Quotient Structures: Example $11.3$