Vanishing Ideal of Larger Subset of Affine Space is Smaller
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Theorem
Let $k$ be a field.
Let $n \ge 1$ be a natural number.
Let $\mathbb A^n_k$ be the standard affine space over $k$.
Let $S \subseteq T \subseteq \mathbb A^n_k$.
Then:
- $\map I S \supseteq \map I T$
where $\map I S$ and $\map I T$ denote the vanishing ideals of $S$ and $T$, respectively.
Proof
\(\ds f\) | \(\in\) | \(\ds \map I T\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in T: \, \) | \(\ds \map f x\) | \(=\) | \(\ds 0\) | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds \map f x\) | \(=\) | \(\ds 0\) | since $S \subseteq T$ by assumption | |||||||||
\(\ds \leadsto \ \ \) | \(\ds f\) | \(\in\) | \(\ds \map I S\) |
$\blacksquare$