Weierstrass Approximation Theorem/Lemma 1
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Theorem
Let $\map {p_{n, k} } t : \N^2 \times \closedint 0 1 \to \R$ be a real valued function defined by:
- $\map {p_{n, k} } t := \dbinom n k t^k \paren {1 - t}^{n - k}$
where:
- $n, k \in \N$
- $t \in \closedint 0 1$
- $\dbinom n k$ denotes the binomial coefficient.
Then:
- $\ds \sum_{k \mathop = 0}^n k \map {p_{n, k} } t = n t$
Proof
From the binomial theorem:
\(\ds \paren {x + y}^n\) | \(=\) | \(\ds \sum_{k \mathop = 0}^n \binom n k y^k x^{n - k}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds 1\) | \(=\) | \(\ds \sum_{k \mathop = 0}^n \binom n k t^k \paren {1 - t}^{n - k}\) | $y = t, ~x = 1 - t$ | ||||||||||
\(\ds 0\) | \(=\) | \(\ds \sum_{k \mathop = 0}^n \binom n k \paren {k t^{k - 1} \paren {1 - t}^{n - k} - t^k \paren{n - k} \paren {1 - t}^{n - k - 1} }\) | Derivative with respect to $t$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \sum_{k \mathop = 0}^n k p_{n,k} \paren {\frac 1 t + \frac 1 {1 - t} } - \frac n {1 - t}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds n t\) | \(=\) | \(\ds \sum_{k \mathop = 0}^n k p_{n,k}\) |
$\blacksquare$
Sources
- 2017: Amol Sasane: A Friendly Approach to Functional Analysis: Chapter $1$: Normed and Banach spaces