Z-Module Associated with Abelian Group is Unitary Z-Module
Theorem
Let $\struct {G, *}$ be an abelian group with identity $e$.
Let $\struct {G, *, \circ}_\Z$ be the $Z$-module associated with $G$.
Then $\struct {G, *, \circ}_\Z$ is a unitary $Z$-module.
Proof
The notation $*^n x$ can be written as $x^n$.
Let us verify that $\struct {G, *, \circ}_\Z$ is a unitary $\Z$-module by verifying the axioms in turn.
Module Axiom $\text M 1$: Distributivity over Module Addition
We need to show that:
- $n \circ \paren {x * y} = \paren {n \circ x} * \paren {n \circ y}$
From the definition:
- $n \circ x = x^n$
and so:
- $n \circ \paren {x * y} = \paren {x * y}^n$
From Power of Product in Abelian Group:
- $\paren {x * y}^n = x^n * y^n = \paren {n \circ x} * \paren {n \circ y}$
$\Box$
Module Axiom $\text M 2$: Distributivity over Scalar Addition
We need to show that:
- $\paren {n + m} \circ x = \paren {n \circ x} * \paren {m \circ x}$
That is:
- $x^{n + m} = x^n * x^m$
This is an instance of Powers of Group Elements: Sum of Indices.
$\Box$
Module Axiom $\text M 3$: Associativity
We need to show that:
- $\paren {n \times m} \circ x = n \circ \paren {m \circ x}$
That is:
- $x^{n m} = \paren {x^m}^n$
This follows directly from Powers of Group Elements: Product of Indices.
$\Box$
Unitary Module Axiom $\text {UM} 4$: Unity of Scalar Ring
We need to show that:
- $\forall x \in G: 1 \circ x = x$
That is:
- $x^1 = x$
This follows from the definition of Power of Group Element.
$\Box$
Having verified all four axioms, we have shown that $\struct {G, *, \circ}_\Z$ is a unitary $\Z$-module.
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {V}$: Vector Spaces: $\S 26$. Vector Spaces and Modules: Example $26.7$