Legendre Polynomial/Examples/P4
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Example of Legendre Polynomial
The $4$th Legendre polynomial is:
- $\map {P_4} x = \dfrac 1 8 \paren {35 x^4 - 30 x^2 + 3}$
Proof
\(\ds \forall n \in \N: \, \) | \(\ds \paren {n + 1} \map {P_{n + 1} } x\) | \(=\) | \(\ds \paren {2 n + 1} x \map {P_n} x - n \map {P_{n - 1} } x\) | Bonnet's Recursion Formula | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds 4 \map {P_4} x\) | \(=\) | \(\ds 7 x \map {P_3} x - 3 \map {P_2} x\) | setting $n = 3$ | ||||||||||
\(\ds \) | \(=\) | \(\ds 7 x \paren {\dfrac 1 2 \paren {5 x^3 - 3 x} } - 3 \paren {\dfrac 1 2 \paren {3 x^2 - 1} }\) | Legendre Polynomial $P_3$ and Legendre Polynomial $P_2$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 2 \paren {35 x^4 - 21 x^2 - 9 x^2 + 3}\) | simplifying | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \map {P_4} x\) | \(=\) | \(\ds \dfrac 1 8 \paren {35 x^4 - 30 x^2 + 3}\) | simplifying |
$\blacksquare$