59,403

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Number

$59 \, 403$ (fifty-nine thousand, four hundred and three) is:

$3 \times 19 \, 801$

The smaller of the $4$th pandigital pair, with $76 \, 182$, of integers each have squares which are themselves pandigital:

$59 \, 403^2 = 3 \, 528 \, 716 \, 409$, $76 \, 182^2 = 5 \, 803 \, 697 \, 124$

Also see

• Previous  ... Next: Pandigital Pairs whose Squares are Pandigital

Sources

• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $57,321$