Cartesian Equation of Conchoid of Nicomedes/Also presented as

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Cartesian Equation of Conchoid of Nicomedes: Also presented as

The directrix of $\KK$ can also be seen expressed in Cartesian coordinates in the form:

$\paren {a - b - x} \paren {a + b - x} x^2 + \paren {a - x}^2 y^2 = 0$


Proof

\(\ds \paren {a - b - x} \paren {a + b - x} x^2 + \paren {a - x}^2 y^2\) \(=\) \(\ds \paren {\paren {a - x} - b} \paren {\paren {a - x} + b} x^2 + \paren {a - x}^2 y^2\)
\(\ds \) \(=\) \(\ds \paren {\paren {a - x}^2 - b^2} x^2 + \paren {a - x}^2 y^2\) Difference of Two Squares
\(\ds \) \(=\) \(\ds \paren {x - a}^2 x^2 - b^2 x^2 + \paren {x - a}^2 y^2\) rearranging
\(\ds \) \(=\) \(\ds \paren {x - a}^2 \paren {x^2 + y^2} - b^2 x^2\) rearranging

from which it follows that the given form is equivalent to:

$\paren {x - a}^2 \paren {x^2 + y^2} = b^2 x^2$

$\blacksquare$


Sources