Category:Primitive of x over a x squared plus b x plus c

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Let $a \in \R_{\ne 0}$.

Then:

$\ds \int \frac {x \rd x} {a x^2 + b x + c} = \frac 1 {2 a} \ln \size {a x^2 + b x + c} - \frac b {2 a} \int \frac {\d x} {a x^2 + b x + c}$

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