Class under Progressing Mapping such that Elements are Sandwiched is Nest

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $A$ be a class.

Let $g: A \to A$ be a progressing mapping on $A$ such that:

$\forall x, y \in A: \map g x \subseteq y \lor y \subseteq x$


Then $A$ is a nest:

$\forall x, y \in A: x \subseteq y \lor y \subseteq x$


Proof

By definition of progressing mapping:

$\forall x \in A: x \subseteq \map g x$

Thus by Subset Relation is Transitive:

$\map g x \subseteq y \implies x \subseteq y$

and it follows that:

$\forall x, y \in A: x \subseteq y \lor y \subseteq x$

Hence the result by definition of nest.

$\blacksquare$


Sources