Cohen's Kappa Statistic/Examples/Medical Diagnosis
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Example of Use of Cohen's Kappa Statistic
Let there be $80$ patients claiming to suffer from depression
Let there be $2$ doctors who are to assess whether or not it is appropriate to treat each patient with a particular antidepressant drug.
In $32$ cases, both agree that treatment is appropriate.
In $35$ cases, both agree that treatment is not appropriate.
In the remaining $13$ cases, they disagree: one doctor believes treatment is appropriate, while the other does not.
Then Cohen's kappa statistic $\kappa$ is evaluated to be:
- $\kappa = 0 \cdotp 675$
Proof
Here we have:
\(\ds N\) | \(=\) | \(\ds 80\) | ||||||||||||
\(\ds n\) | \(=\) | \(\ds 32 + 35 = 67\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds p_{\mathrm {obs} }\) | \(=\) | \(\ds \dfrac n N = 0 \cdotp 8375\) | |||||||||||
\(\ds p_{\mathrm {exp} }\) | \(=\) | \(\ds \dfrac {40} {80} = 0 \cdotp 5\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \kappa\) | \(=\) | \(\ds \dfrac {p_{\mathrm {obs} } - p_{\mathrm {exp} } } {1 - p_{\mathrm {exp} } }\) | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {0 \cdotp 8375 - 0 \cdotp 5} {1 - 0 \cdotp 5}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 0 \cdotp 675\) |
$\blacksquare$
Sources
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): Cohen's kappa statistic