Complex Conjugate Coordinates/Examples/(x-3)^2 + y^2 = 9

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Example of Complex Conjugate Coordinates

The equation of the circle:

$\paren {x - 3}^2 + y^2 = 9$

can be expressed in complex conjugate coordinates as:

$\paren {z - 3} \paren {\overline z - 3} = 9$


Proof

\(\ds \paren {x - 3}^2 + y^2\) \(=\) \(\ds 9\)
\(\ds \leadstoandfrom \ \ \) \(\ds \paren {\paren {x - 3} + i y} \paren {\paren {x - 3} - i y}\) \(=\) \(\ds 9\)
\(\ds \leadstoandfrom \ \ \) \(\ds \paren {\paren {x + i y} - 3} \paren {\paren {x - i y} - 3}\) \(=\) \(\ds 9\)
\(\ds \leadstoandfrom \ \ \) \(\ds \paren {z - 3} \paren {\overline z - 3}\) \(=\) \(\ds 9\) as $z = x + i y$, $\overline z = x - i y$

$\blacksquare$


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