Convergent Sequence in Topological Vector Space is Cauchy
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Theorem
Let $\struct {X, \tau}$ be a topological vector space.
Let $\sequence {x_n}_{n \mathop \in \N}$ be a convergent sequence with $x_n \to x$.
Then $\sequence {x_n}_{n \mathop \in \N}$ is Cauchy.
Proof
Let $V$ be an open neighborhood of ${\mathbf 0}_X$.
From Open Neighborhood of Point in Topological Vector Space contains Sum of Open Neighborhoods: Corollary $1$, there exists a symmetric open neighborhood $U$ of ${\mathbf 0}_X$ such that:
- $U + U \subseteq V$
Since $x_n \to x$, there exists $N \in \N$ such that:
- $x_n \in x + U$
for $n \ge N$.
Since $U$ is symmetric, we have $U = -U$ and so:
- $-x_m \in -x + U$
for $m \ge N$.
Then we have:
- $x_n - x_m \in U + U \subseteq V$
for $n, m \ge N$.
So $\sequence {x_n}_{n \mathop \in \N}$ is Cauchy.
$\blacksquare$