Derivative of Composite Function/Examples/Exponential of x^2 + x + 1
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Example of Derivative of Composite Function
- $\map {\dfrac \d {\d x} } {e^{x^2 + x + 1} } = \paren {2 x + 1} e^{x^2 + x + 1}$
Proof
Let $u = x^2 + x + 1$.
Let $y = e^u$.
Thus we have:
- $y = e^{x^2 + x + 1}$
and so:
\(\ds \dfrac {\d y} {\d x}\) | \(=\) | \(\ds \dfrac {\d y} {\d u} \dfrac {\d u} {\d x}\) | Derivative of Composite Function | |||||||||||
\(\ds \) | \(=\) | \(\ds e^u \paren {\map {\dfrac \d {\d x} } {x^2} + \map {\dfrac \d {\d x} } x + \map {\dfrac \d {\d x} } 1}\) | Derivative of Exponential Function, Sum Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds e^u \paren {2 x + 1}\) | Power Rule for Derivatives, Derivative of Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {2 x + 1} e^{x^2 + x + 1}\) | simplification |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text {II}$. Calculus: Differentiation: Exercises $\text {IX}$: $24$.