Directed iff Filtered in Dual Ordered Set

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $\struct {S, \preceq_1}$ be an ordered set.

Let $\struct {S, \preceq_2}$ be a dual ordered set of $\struct {S, \preceq_1}$

Let $X \subseteq S$.


Then:

$X$ is directed in $\struct {S, \preceq_1}$

if and only if:

$X$ is filtered in $\struct {S, \preceq_2}$.


Proof

Sufficient Condition

Assume that:

$X$ is directed in $\struct {S, \preceq_1}$

Thus $X$ is non-empty.

Let $x, y \in S$.

By definition of directed:

$\exists z \in S: x \preceq_1 z \land y \preceq_1 z$

Thus by definition of dual ordered set:

$z \preceq_2 x \land z \preceq_2 y$

$\Box$


Necessary Condition

Assume that:

$X$ is filtered in $\struct {S, \preceq_2}$

Thus $X$ is non-empty.

Let $x, y \in S$.

By definition of filtered:

$\exists z \in S: z \preceq_2 x \land z \preceq_2 y$

Thus by definition of dual ordered set:

$x \preceq_1 z \land y \preceq_1 z$

$\blacksquare$


Sources