Directed iff Filtered in Dual Ordered Set
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Theorem
Let $\struct {S, \preceq_1}$ be an ordered set.
Let $\struct {S, \preceq_2}$ be a dual ordered set of $\struct {S, \preceq_1}$
Let $X \subseteq S$.
Then:
- $X$ is directed in $\struct {S, \preceq_1}$
- $X$ is filtered in $\struct {S, \preceq_2}$.
Proof
Sufficient Condition
Assume that:
- $X$ is directed in $\struct {S, \preceq_1}$
Thus $X$ is non-empty.
Let $x, y \in S$.
By definition of directed:
- $\exists z \in S: x \preceq_1 z \land y \preceq_1 z$
Thus by definition of dual ordered set:
- $z \preceq_2 x \land z \preceq_2 y$
$\Box$
Necessary Condition
Assume that:
- $X$ is filtered in $\struct {S, \preceq_2}$
Thus $X$ is non-empty.
Let $x, y \in S$.
By definition of filtered:
- $\exists z \in S: z \preceq_2 x \land z \preceq_2 y$
Thus by definition of dual ordered set:
- $x \preceq_1 z \land y \preceq_1 z$
$\blacksquare$
Sources
- Mizar article YELLOW_7:26