Divisor Sum of 12,496
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Example of Divisor Sum of Integer
- $\map {\sigma_1} {12 \, 496} = 26 \, 784$
where $\sigma_1$ denotes the divisor sum function.
Proof
- $\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$
where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.
We have that:
- $12 \, 496 = 2^4 \times 11 \times 71$
Hence:
\(\ds \map {\sigma_1} {12 \, 496}\) | \(=\) | \(\ds \frac {2^5 - 1} {2 - 1} \times \frac {11^2 - 1} {11 - 1} \times \frac {71^2 - 1} {71 - 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {31} 1 \times \frac {12 \times 10} {10} \times \frac {72 \times 70} {70}\) | Difference of Two Squares | |||||||||||
\(\ds \) | \(=\) | \(\ds 31 \times 12 \times 72\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 31 \times \paren {2^2 \times 3} \times \paren {2^3 \times 3^2}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^5 \times 3^3 \times 31\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 26 \, 784\) |
$\blacksquare$