Divisor Sum of 64

From ProofWiki
Jump to navigation Jump to search

Example of Divisor Sum of Integer

$\map {\sigma_1} {64} = 127$

where $\sigma_1$ denotes the divisor sum.


Proof

We have that:

$64 = 2^6$


Hence:

\(\ds \map {\sigma_1} {64}\) \(=\) \(\ds 2 \times 7 - 1\) Divisor Sum of Power of 2
\(\ds \) \(=\) \(\ds 127\)

$\blacksquare$