Divisor Sum of 76

From ProofWiki
Jump to navigation Jump to search

Example of Divisor Sum of Integer

$\map {\sigma_1} {76} = 140$

where $\sigma_1$ denotes the divisor sum function.


Proof

From Divisor Sum of Integer

$\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$

where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.


We have that:

$76 = 2^2 \times 19$


Hence:

\(\ds \map {\sigma_1} {76}\) \(=\) \(\ds \frac {2^3 - 1} {2 - 1} \times \frac {19^2 - 1} {19 - 1}\)
\(\ds \) \(=\) \(\ds \frac 7 1 \times \frac {360} {18}\)
\(\ds \) \(=\) \(\ds 7 \times 20\)
\(\ds \) \(=\) \(\ds 140\)

$\blacksquare$