Equivalence of Definitions of Normal Subset/2 implies 3
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Theorem
Let $\left({G, \circ}\right)$ be a group.
Let $S \subseteq G$.
Let $S$ be a normal subset of $G$ by Definition 2.
Then $S$ is a normal subset of $G$ by Definition 3.
That is, if:
- $\forall g \in G: g \circ S \circ g^{-1} = S$
or:
- $\forall g \in G: g^{-1} \circ S \circ g = S$
then:
- $\forall g \in G: g \circ S \circ g^{-1} \subseteq S$
and:
- $\forall g \in G: g^{-1} \circ S \circ g \subseteq S$
Proof
We have that:
- $\left({\forall g \in G: g \circ S \circ g^{-1} = S}\right) \iff \left({\forall g \in G: g^{-1} \circ S \circ g = S}\right)$
The result follows by definition of set equality.
$\blacksquare$