Equivalence of Definitions of Normal Subset/3 iff 5
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Theorem
Let $\struct {G, \circ}$ be a group.
Let $S \subseteq G$.
Then:
- $S$ is a normal subset of $G$ by Definition 3
- $S$ is a normal subset of $G$ by Definition 5.
Proof
3 implies 5
Suppose that $S$ is a normal subset of $G$ by Definition 3.
That is:
- $\forall g \in G: g^{-1} \circ S \circ g \subseteq S$.
Let $x, y \in G$ such that $x \circ y \in S$.
Then:
\(\ds y \circ x\) | \(=\) | \(\ds e \circ \paren {y \circ x}\) | Group Axiom $\text G 2$: Existence of Identity Element | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {x^{-1} \circ x} \circ \paren {y \circ x}\) | Group Axiom $\text G 3$: Existence of Inverse Element | |||||||||||
\(\ds \) | \(=\) | \(\ds x^{-1} \circ \paren {x \circ y} \circ x\) | Group Axiom $\text G 1$: Associativity | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds y \circ x\) | \(\in\) | \(\ds x^{-1} \circ S \circ x\) | $x \circ y \in S$ | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds y \circ x\) | \(\in\) | \(\ds S\) | by hypothesis: Definition 3 of Normal Subset |
$\Box$
5 implies 3
Suppose that $S$ is a normal subset of $G$ by Definition 5.
That is:
- $\forall x, y \in G: x \circ y \in S \implies y \circ x \in S$
Let $g \in G$.
Then:
\(\ds \forall x \in S: \, \) | \(\ds e \circ x \circ e\) | \(\in\) | \(\ds S\) | Group Axiom $\text G 2$: Existence of Identity Element | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds \paren {g \circ g^{-1} } \circ x \circ \paren {g \circ g^{-1} }\) | \(\in\) | \(\ds S\) | Group Axiom $\text G 3$: Existence of Inverse Element | |||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds g \circ \paren {g^{-1} \circ x \circ g \circ g^{-1} }\) | \(\in\) | \(\ds S\) | Group Axiom $\text G 1$: Associativity | |||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds \paren {g^{-1} \circ x \circ g \circ g^{-1} } \circ g\) | \(\in\) | \(\ds S\) | by hypothesis: Definition 5 of Normal Subset | |||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds \paren {g^{-1} \circ x \circ g} \circ \paren {g^{-1} \circ g}\) | \(\in\) | \(\ds S\) | Group Axiom $\text G 1$: Associativity | |||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds \paren {g^{-1} \circ x \circ g} \circ e\) | \(\in\) | \(\ds S\) | Definition of Inverse Element | |||||||||
\(\ds \leadsto \ \ \) | \(\ds \forall x \in S: \, \) | \(\ds g^{-1} \circ x \circ g\) | \(\in\) | \(\ds S\) | Definition of Identity Element | |||||||||
\(\ds \leadsto \ \ \) | \(\ds g^{-1} \circ S \circ g\) | \(\subseteq\) | \(\ds S\) | Definition of Subset Product |
$\blacksquare$