Excluded Point Topology is T4/Proof 2
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Theorem
Let $T = \struct {S, \tau_{\bar p} }$ be an excluded point space.
Then $T$ is a $T_4$ space.
Proof
We have:
- Excluded Point Topology is Open Extension Topology of Discrete Topology
- Open Extension Topology is $T_4$
Hence the result.
$\blacksquare$