Existence of Inverse of Class Relation

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Theorem

Let $X$ be a class.

Then there is a class $Z$ such that, for all sets $u, v$:

$\tuple {u, v} \in Z \iff \tuple {v, u} \in X$

where $\tuple {\cdot, \cdot}$ denotes the Kuratowski formalization of ordered pairs.


Proof

Let $X$ be arbitrary.

By Axiom $\text B 5$, there is a class $Z_1$ such that:

$\paren 1 \quad \forall a, w: \tuple {a, w} \in Z_1 \iff a \in X$

Now, by Axiom $\text B 7$, there is a class $Z_2$ such that:

$\paren 2 \quad \forall u, v, w: \tuple {\tuple {v, w}, u} \in Z_2 \iff \tuple {\tuple {v, u}, w} \in Z_1$

Next, by Axiom $\text B 6$, there is a class $Z_3$ such that:

$\paren 3 \quad \forall u, v, w: \tuple {\tuple {u, v}, w} \in Z_3 \iff \tuple {\tuple {v, w}, u} \in Z_2$

Finally, by Axiom $\text B 4$, there is a class $Z$ such that:

$\paren 4 \quad \forall b: b \in Z \iff \exists w: \tuple {b, w} \in Z_3$

We will prove that the $Z$ as defined above satisfies the theorem.


First, choose $a := \tuple {v, u}$ in $\paren 1$, to get:

$\paren {1'} \quad \forall u, v, w: \tuple {\tuple {v, u}, w} \in Z_1 \iff \tuple {v, u} \in X$

Also, choose $b := \tuple {u, v}$ in $\paren 4$, to get:

$\paren {4'} \quad \forall u, v: \tuple {u, v} \in Z \iff \exists w: \tuple {\tuple {u, v}, w} \in Z_3$

By Biconditional is Transitive with $\paren 2$ and $\paren 3$, for any $u, v, w$:

$\paren {2,3} \quad \tuple {\tuple {u, v}, w} \in Z_3 \iff \tuple {\tuple {v, u}, w} \in Z_1$


Now, we can proceed with the equivalence proof.

Suppose $\tuple {v, u} \in X$ for some sets $u, v$.

By the Axiom of Infinity, there exists at least one set $c$.

Then, by $\paren {1'}$:

$\tuple {\tuple {v, u}, c} \in Z_1$

Thus, by $\paren {2,3}$:

$\tuple {\tuple {u, v}, c} \in Z_3$

Hence, by $\paren {4'}$, choosing $w := c$:

$\tuple {u, v} \in Z$

$\Box$

Lastly, suppose $\tuple {u, v} \in Z$ for some sets $u, v$.

By $\paren {4'}$, there is some set $w_0$ such that:

$\tuple {\tuple {u, v}, w_0} \in Z_3$

Then, by $\paren {2,3}$:

$\tuple {\tuple {v, u}, w_0} \in Z_1$

Thus, by $\paren {1'}$, choosing $w := w_0$:

$\tuple {v, u} \in X$

$\blacksquare$