False Statement implies Every Statement/Formulation 1/Proof 1

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\(\ds \neg p\) \(\) \(\ds \)
\(\ds \vdash \ \ \) \(\ds p \implies q\) \(\) \(\ds \)


By the tableau method of natural deduction:

$\neg p \vdash p \implies q$
Line Pool Formula Rule Depends upon Notes
1 1 $\neg p$ Premise (None)
2 1 $\neg p \lor q$ Rule of Addition: $\lor \II_1$ 1
3 1 $p \implies q$ Sequent Introduction 2 Rule of Material Implication