Four Fours/73

Puzzle

Using exactly $4$ instances of the number $4$, the task is to write an expression for $73$, using whatever arithmetical operations you consider necessary.

Solutions

Solution $1$

$73 = \dfrac {4! + 4! + \sqrt {. \dot 4} } {\sqrt {. \dot 4} }$

Solution $2$

$73 = \dfrac {4! \times \sqrt 4 + \sqrt {. \dot 4} } {\sqrt {. \dot 4} }$

Also see

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