Four Fours/Lemmata/Three Fours/26
< Four Fours | Lemmata | Three Fours
Jump to navigation
Jump to search
Puzzle
Using exactly $3$ instances of the number $4$, the task is to write an expression for $26$, using whatever arithmetical operations you consider necessary.
Solutions
Solution $1$
- $26 = 4! + 4 - \sqrt 4$