Greatest Element is Upper Bound

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Let $\struct {S, \preceq}$ be an ordered set.

Let $T \subseteq S$.

Let $T$ have a greatest element $M \in T$.

Then $M$ is an upper bound of $T$.

It follows by definition that $T$ is bounded above.


Let $M \in T$ be a greatest element of $T$.

By definition:

$\forall y \in T: y \preceq M$

But as $T \subseteq S$, it follows that $M \in S$.


$\exists M \in S: \forall y \in T: y \preceq M$

Thus $T$ is bounded above by the upper bound $M$.


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