Group of Order 35 is Cyclic Group/Proof 1

Theorem

Let $G$ be a group whose order is $35$.

Then $G$ is cyclic.

Proof

We have that $35 = 5 \times 7$.

Then we have that $5$ and $7$ are primes such that $5 < 7$ and $5$ does not divide $7 - 1$.

Thus Group of Order $p q$ is Cyclic can be applied.

$\blacksquare$