Identity Mapping is Right Identity
Theorem
Let $S$ and $T$ be sets.
Let $f: S \to T$ be a mapping.
Then:
- $f \circ I_S = f$
where $I_S$ is the identity mapping on $S$, and $\circ$ signifies composition of mappings.
Proof 1
Equality of Codomains
The codomains of $f$ and $f \circ I_S$ are both equal to $T$ from Codomain of Composite Relation.
$\Box$
Equality of Domains
From Domain of Composite Relation:
- $\Dom {f \circ I_S} = \Dom {I_S}$
But from the definition of the identity mapping:
- $\Dom {I_S} = \Img {I_S} = S$
$\Box$
Equality of Mappings
The composite of $I_S$ and $f$ is defined as:
- $f \circ I_S = \set {\tuple {x, z} \in S \times T: \exists y \in S: \tuple {x, y} \in I_S \land \tuple {y, z} \in f}$
But by definition of the identity mapping on $S$, we have that:
- $\tuple {x, y} \in I_S \implies x = y$
Hence:
- $f \circ I_S = \set {\tuple {y, z} \in S \times T: \exists y \in S: \tuple {y, y}\ \in I_S \land \tuple {y, z} \in f}$
But as $\forall y \in S: \tuple {y, y} \in I_S$, this means:
- $f \circ I_S = \set {\tuple {y, z} \in S \times T: \tuple {y, z} \in f}$
That is:
- $f \circ I_S = f$
$\Box$
Hence the result, by Equality of Mappings.
$\blacksquare$
Proof 2
By definition, a mapping is also a relation.
Also by definition, the identity mapping is the same as the diagonal relation.
Thus Diagonal Relation is Right Identity can be applied directly.
$\blacksquare$
Also see
Sources
- 1951: Nathan Jacobson: Lectures in Abstract Algebra: Volume $\text { I }$: Basic Concepts ... (previous) ... (next): Introduction $\S 2$: Product sets, mappings
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text I$: Algebraic Structures: $\S 5$: Composites and Inverses of Functions
- 1967: George McCarty: Topology: An Introduction with Application to Topological Groups ... (previous) ... (next): Chapter $\text{I}$: Sets and Functions: Composition of Functions
- 1971: Allan Clark: Elements of Abstract Algebra ... (previous) ... (next): Chapter $1$: Mappings: $\S 16$
- 1971: Robert H. Kasriel: Undergraduate Topology ... (previous) ... (next): $\S 1.14$: Composition of Functions: Theorem $14.7$
- 1982: P.M. Cohn: Algebra Volume 1 (2nd ed.) ... (previous) ... (next): Chapter $1$: Sets and mappings: $\S 1.3$: Mappings
- 1996: John F. Humphreys: A Course in Group Theory ... (previous) ... (next): Chapter $2$: Maps and relations on sets: Definition $2.11$
- 1996: H. Jerome Keisler and Joel Robbin: Mathematical Logic and Computability ... (previous) ... (next): Appendix $\text{A}.5$: Identity, One-one, and Onto Functions
- 2010: Steve Awodey: Category Theory (2nd ed.) ... (previous) ... (next): $\S 1.2$