Inclusion Mapping on Subgroup is Monomorphism

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $\struct {G, \circ}$ be a group.

Let $\struct {H, \circ {\restriction_H} }$ be a subgroup of $G$.

Let $i: H \to G$ be the inclusion mapping from $H$ to $G$.


Then $i$ is a group monomorphism.


Proof

We have:

The result follows by definition of (group) monomorphism.

$\blacksquare$


Sources