Integer as Sums and Differences of Consecutive Squares/Examples

From ProofWiki
Jump to navigation Jump to search

Example of use of Integer as Sums and Differences of Consecutive Squares

Since the proof above is constructive, we can follow the proof and derive:

\(\ds 15\) \(=\) \(\ds 3 + 4 + 4 + 4\)
\(\ds \) \(=\) \(\ds \paren {- 1^2 + 2^2} + \paren {3^2 - 4^2 - 5^2 + 6^2} + \paren {7^2 - 8^2 - 9^2 + 10^2} + \paren {11^2 - 12^2 - 13^2 + 14^2}\)

and its associated family of solutions:

\(\ds 15\) \(=\) \(\ds - 1^2 + 2^2 + 3^2 - 4^2 - 5^2 + 6^2 + 7^2 - 8^2 - 9^2 + 10^2 + 11^2 - 12^2 - 13^2 + 14^2 + 15^2 - 16^2 - 17^2 + 18^2 - 19^2 + 20^2 + 21^2 - 22^2\)

and so on.

However this may not give the least number of squares that this works for.

In fact we have:

\(\ds 15\) \(=\) \(\ds 1^2 - 2^2 + 3^2 - 4^2 + 5^2\)

from Triangular Number as Alternating Sum and Difference of Squares.