Intersection of Zero Loci is Zero Locus
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Theorem
Let $k$ be a field.
Let $n \in \N_{>0}$.
Let $A = k \sqbrk {X_1, \ldots, X_n}$ be the ring of polynomials in $n$ variables over $k$.
Let $\mathbb S \subseteq \powerset A$ be a subset of the power set of $A$.
Then:
- $\ds \bigcap _{S \mathop \in \mathbb S} \map V S = \map V {\bigcup \mathbb S}$
where $\map V \cdot$ denotes the zero locus.
Proof
\(\ds x\) | \(\in\) | \(\ds \bigcap_{S \mathop \in \mathbb S} \map V S\) | ||||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \forall S \in \mathbb S: \, \) | \(\ds x\) | \(\in\) | \(\ds \map V S\) | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \forall S \in \mathbb S: \forall f \in S: \, \) | \(\ds \map f x\) | \(=\) | \(\ds 0\) | Definition of Zero Locus of Set of Polynomials | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \forall f \in \bigcup \mathbb S: \, \) | \(\ds \map f x\) | \(=\) | \(\ds 0\) | ||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds x\) | \(\in\) | \(\ds \map V {\bigcup \mathbb S}\) |
$\blacksquare$