Klein Four-Group as Subgroup of S4
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Theorem
Let $G$ be the following subset of the symmetric group on $4$ letters $S_4$, expressed in two-row notation:
\(\ds e\) | \(=\) | \(\ds \begin{bmatrix} 1 & 2 & 3 & 4 \\ 1 & 2 & 3 & 4 \end{bmatrix}\) | ||||||||||||
\(\ds a\) | \(=\) | \(\ds \begin{bmatrix} 1 & 2 & 3 & 4 \\ 2 & 1 & 4 & 3 \end{bmatrix}\) | ||||||||||||
\(\ds b\) | \(=\) | \(\ds \begin{bmatrix} 1 & 2 & 3 & 4 \\ 3 & 4 & 1 & 2 \end{bmatrix}\) | ||||||||||||
\(\ds c\) | \(=\) | \(\ds \begin{bmatrix} 1 & 2 & 3 & 4 \\ 4 & 3 & 2 & 1 \end{bmatrix}\) |
Then $G$ is an example of the Klein $4$-group.
Proof
By inspection, the Cayley table is constructed:
- $\begin{array}{c|cccc}
& e & a & b & c \\
\hline e & e & a & b & c \\ a & a & e & c & b \\ b & b & c & e & a \\ c & c & b & a & e \\ \end{array}$
Again by inspection this can be seen to be the same as the Cayley table for the Klein $4$-group.
$\blacksquare$
Sources
- 1978: Thomas A. Whitelaw: An Introduction to Abstract Algebra ... (previous) ... (next): $\S 44$. Some consequences of Lagrange's Theorem: Illustration $2$