Kummer's Hypergeometric Theorem/Proof 3
Jump to navigation
Jump to search
Theorem
- $\map F {n, -x; x + n + 1; -1} = \dfrac {\map \Gamma {x + n + 1} \map \Gamma {\dfrac n 2 + 1} } {\map \Gamma {x + \dfrac n 2 + 1} \map \Gamma {n + 1} }$
Proof
From Kummer's Quadratic Transformation, we have:
- $\ds \map F {a, b; 1 + a - b; z} = \paren {1 - z}^{-a} \map F {\dfrac a 2, \dfrac {1 + a} 2 - b; 1 + a - b; \dfrac {-4 z} {\paren {1 - z }^2} }$
Let $z \to -1$ and we have:
- $\ds \map F {a, b; 1 + a - b; -1} = 2^{-a} \map F {\dfrac a 2, \dfrac {1 + a} 2 - b; 1 + a - b; 1 }$
From Gauss's Hypergeometric Theorem, we have:
- $\map F {a, b; c; 1} = \dfrac {\map \Gamma c \map \Gamma {c - a - b} } {\map \Gamma {c - a} \map \Gamma {c - b} }$
Therefore, the right hand side becomes:
\(\ds 2^{-a} \map F {\dfrac a 2, \dfrac {1 + a} 2 - b; 1 + a - b; 1 }\) | \(=\) | \(\ds 2^{-a} \dfrac {\map \Gamma {1 + a - b} \map \Gamma {\paren {1 + a - b} - \dfrac a 2 - \paren {\dfrac {1 + a} 2 - b} } } {\map \Gamma {\paren {1 + a - b} - \dfrac a 2} \map \Gamma {\paren {1 + a - b} - \paren {\dfrac {1 + a} 2 - b} } }\) | Gauss's Hypergeometric Theorem | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\map \Gamma {1 + a - b} } {\map \Gamma {1 + \dfrac a 2 - b} } \paren {2^{-a} \dfrac {\map \Gamma {\dfrac 1 2 } } {\map \Gamma {\dfrac {1 + a} 2 } } }\) | simplifying | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\map \Gamma {1 + a - b} } {\map \Gamma {1 + \dfrac a 2 - b} } \paren {\dfrac {\map \Gamma {\dfrac a 2 + 1 } } {\map \Gamma {a + 1 } } }\) | Legendre's Duplication Formula | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\map \Gamma {1 + a - b} \map \Gamma {\dfrac a 2 + 1 } } {\map \Gamma {1 + \dfrac a 2 - b} \map \Gamma {a + 1 } }\) | simplifying |
Substituting $a = n$ and $b = -x$, we obtain:
\(\ds \map F {a, b; 1 + a - b; -1}\) | \(=\) | \(\ds \dfrac {\map \Gamma {1 + a - b} \map \Gamma {\dfrac a 2 + 1 } } {\map \Gamma {1 + \dfrac a 2 - b} \map \Gamma {a + 1 } }\) | before substitution | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \map F {n, -x; 1 + n + x; -1}\) | \(=\) | \(\ds \dfrac {\map \Gamma {1 + n + x} \map \Gamma {\dfrac n 2 + 1 } } {\map \Gamma {1 + \dfrac n 2 + x} \map \Gamma {n + 1 } }\) | after substitution |
$\blacksquare$
Source of Name
This entry was named for Ernst Eduard Kummer.
Sources
- 1935: W.N. Bailey: Generalized Hypergeometric Series Chapter $\text {2}$. The hypergeometric series